isSetEqual

Compare two sets for shallow equality

Usage

Returns true when two Set instances contain the same values (compared by reference).

import * as 
import _
_ from 'radashi'

const 
const left: Set<string>
left = new 
var Set: SetConstructor
new <string>(iterable?: Iterable<string> | null | undefined) => Set<string> (+1 overload)
Set(['a', 'b', 'c'])
const 
const right: Set<string>
right = new 
var Set: SetConstructor
new <string>(iterable?: Iterable<string> | null | undefined) => Set<string> (+1 overload)
Set(['c', 'b', 'a'])

import _
_.
function isSetEqual(x: Set<any>, y: Set<any>): boolean
Check if two sets are equal.
Note: This does NOT check for deep equality of the items.
@see ― https://radashi.js.org/reference/typed/isSetEqual
@version ― 12.7.0
isSetEqual(
const left: Set<string>
left, 
const right: Set<string>
right) // => true

const 
const object: {
    id: number;
}
object = { 
id: number
id: 1 }

import _
_.
function isSetEqual(x: Set<any>, y: Set<any>): boolean
Check if two sets are equal.
Note: This does NOT check for deep equality of the items.
@see ― https://radashi.js.org/reference/typed/isSetEqual
@version ― 12.7.0
isSetEqual(new 
var Set: SetConstructor
new <{
    id: number;
}>(iterable?: Iterable<{
    id: number;
}> | null | undefined) => Set<{
    id: number;
}> (+1 overload)
Set([
const object: {
    id: number;
}
object]), new 
var Set: SetConstructor
new <{
    id: number;
}>(iterable?: Iterable<{
    id: number;
}> | null | undefined) => Set<{
    id: number;
}> (+1 overload)
Set([{ 
id: number
id: 1 }])) // => false

Entries are matched using Set#has, so two values are considered equal only if they are the same reference.